(-0.25x^2)+2x+5=0

Solution for (-0.25x^2)+2x+5=0 equation:

(-0.25x^2)+2x+5=0

We get rid of parentheses

-0.25x^2+2x+5=0

a = -0.25; b = 2; c = +5;
Δ = b2-4ac
Δ = 22-4·(-0.25)·5
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-3}{2*-0.25}=\frac{-5}{-0.5}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+3}{2*-0.25}=\frac{1}{-0.5}
=-2
$